1 条题解

  • 1
    @ 2025-5-12 19:16:39
    #include <bits/stdc++.h>
    using namespace std;
    #define ls u << 1
    #define rs u << 1 | 1
    #define LL long long
    #define int long long
    #define PII pair <int, int>
    #define fi first
    #define se second
    #define pub push_back
    #define pob pop_back
    #define puf push_front
    #define pof pop_front
    #define lb lower_bound
    #define ub upper_bound
    #define i128 __int128
    #define pcnt(x) __builtin_popcount(x)
    #define mem(a,goal) memset(a, (goal), sizeof(a))
    #define rep(x,start,end) for(int x = (start) - ((start) > (end)); x != (end) - ((start) > (end)); ((start) < (end) ? x ++ : x --))
    #define aLL(x) (x).begin(), (x).end()
    #define sz(x) (int)(x).size()
    const int INF = 998244353;
    const int mod = 1e9 + 7;
    const int N = 100010;
    int a[N];
    
    void solve()
    {
        int n;
        cin >> n;
        int res = -1;
        vector<int> a(n, 0), cnt(31, 0);
        for(int i = 0; i < n; ++ i)
        {
            cin >> a[i];
            for(int j = 0; j < 31; ++ j)
            {
                if(a[i] >> j & 1) cnt[j] ++;
            }
        }
        for(int i = 0; i < n; ++ i)
        {
            int t = 0;
            for(int j = 0; j < 31; ++ j)
            {
                int tmp = a[i] >> j & 1;
                if(tmp) t += (1 << j) * (n - cnt[j]);
                else t += (1 << j) * cnt[j];
            }
            res = max(res, t);
        }
        cout << res << '\n';
    }
    
    signed main()
    {
        int t = 1;
        cin >> t;
        while (t --) solve();
        return 0;
    }
    
    • 1

    信息

    ID
    5574
    时间
    2000ms
    内存
    256MiB
    难度
    10
    标签
    递交数
    1
    已通过
    1
    上传者