1 条题解
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1
#include <bits/stdc++.h> using namespace std; #define ls u << 1 #define rs u << 1 | 1 #define LL long long #define int long long #define PII pair <int, int> #define fi first #define se second #define pub push_back #define pob pop_back #define puf push_front #define pof pop_front #define lb lower_bound #define ub upper_bound #define i128 __int128 #define pcnt(x) __builtin_popcount(x) #define mem(a,goal) memset(a, (goal), sizeof(a)) #define rep(x,start,end) for(int x = (start) - ((start) > (end)); x != (end) - ((start) > (end)); ((start) < (end) ? x ++ : x --)) #define aLL(x) (x).begin(), (x).end() #define sz(x) (int)(x).size() const int INF = 998244353; const int mod = 1e9 + 7; const int N = 2010; int a[N][N], b[N][N]; void insert(int x1, int y1, int x2, int y2, int c) { b[x1][y1] += c; b[x1][y2 + 1] -= c; b[x2 + 1][y1] -= c; b[x2 + 1][y2 + 1] += c; } void solve() { int n, m; cin >> n >> m; for(int j = 1; j <= m; ++ j) { int x1, y1, x2, y2; cin >> x1 >> y1 >> x2 >> y2; insert(x1, y1, x2, y2, 1); } for(int i = 1; i <= n; ++ i) { for(int j = 1; j <= n; ++ j) { b[i][j] += b[i - 1][j] + b[i][j - 1] - b[i - 1][j - 1]; if(b[i][j] & 1) cout << 1; else cout << '0'; } cout << '\n'; } } signed main() { int t = 1; while (t --) solve(); return 0; }
- 1
信息
- ID
- 5556
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 10
- 标签
- 递交数
- 1
- 已通过
- 1
- 上传者