1 条题解

  • 1
    @ 2025-5-17 14:11:21
    #include <bits/stdc++.h>
    using namespace std;
    #define ls u << 1
    #define rs u << 1 | 1
    #define LL long long
    #define int long long
    #define PII pair <int, int>
    #define fi first
    #define se second
    #define pub push_back
    #define pob pop_back
    #define puf push_front
    #define pof pop_front
    #define lb lower_bound
    #define ub upper_bound
    #define i128 __int128
    #define pcnt(x) __builtin_popcount(x)
    #define mem(a,goal) memset(a, (goal), sizeof(a))
    #define rep(x,start,end) for(int x = (start) - ((start) > (end)); x != (end) - ((start) > (end)); ((start) < (end) ? x ++ : x --))
    #define aLL(x) (x).begin(), (x).end()
    #define sz(x) (int)(x).size()
    const int INF = 998244353;
    const int mod = 1e9 + 7;
    const int N = 2010;
    int a[N][N], b[N][N];
    
    void insert(int x1, int y1, int x2, int y2, int c)
    {
        b[x1][y1] += c;
        b[x1][y2 + 1] -= c;
        b[x2 + 1][y1] -= c;
        b[x2 + 1][y2 + 1] += c;
    }
    void solve()
    {
        int n, m;
        cin >> n >> m;
        
        for(int j = 1; j <= m; ++ j)
        {
            int x1, y1, x2, y2;
            cin >> x1 >> y1 >> x2 >> y2;
            insert(x1, y1, x2, y2, 1);
        }
        
        for(int i = 1; i <= n; ++ i)
        {
            for(int j = 1; j <= n; ++ j)
            {
                b[i][j] += b[i - 1][j] + b[i][j - 1] - b[i - 1][j - 1];
                if(b[i][j] & 1) cout << 1;
                else cout << '0';
            }
            cout << '\n';
        }
    
    }
    
    signed main()
    {
        int t = 1;
        while (t --) solve();
        return 0;
    }
    
    • 1

    信息

    ID
    5556
    时间
    1000ms
    内存
    256MiB
    难度
    10
    标签
    递交数
    1
    已通过
    1
    上传者