2 条题解

  • 0
    @ 2025-10-17 0:22:34

    a = input() zimu = list(map(str, a)) yuan = 'aeiou' for yuanyin in reversed(a): if yuanyin in yuan: print(yuanyin) break

    • 0
      @ 2024-11-24 23:55:45
      #include <iostream>
      #include <string>
      using namespace std;
      int main()
      {
          string s;
          cin >> s;
      
          for(int i = s.size() - 1; i >= 0; -- i)
          {
              if(s[i] == 'a' || s[i] == 'e' || s[i] == 'i'|| s[i] == 'o'|| s[i] == 'u')
              {
                  cout << s[i];
                  return 0;
              }
          }
          return 0;
      }
      
      • 1

      信息

      ID
      5512
      时间
      1000ms
      内存
      256MiB
      难度
      7
      标签
      递交数
      18
      已通过
      10
      上传者